html solve some question pleas read the instruction need as HTML page Q1 The power of each four digit number in base 16 and their equivalent base 2 are provided in the table below: Base 16 163=4096 162=256 161=16 160=1 Base 2 212=4096 28=256 24=16 20=1 We have to raising 16 to the power of 0,1,2 and 3 to find out the power of each digit. When converting to base 2 we know that 16=24.however we see that 1=24Ã—0. 16=24Ã—1. 256=24Ã—2=28.4096=24Ã—3=212. Q2 Convert the hexadecimal number 3D7 to decimal This question pertains to converting between number bases. In order to do so I have used the multiplication method to convert from another number base to base 10. 3Ã—16=48 48+13=61 61Ã—16=976 976+7=983 Therefore the equivalent to 3D7 base 16 in base 10 is 983. Q3 Convert the binary number 11001011101 to Base-4. 121131 q6 Convert the binary number 111100111100111100 to Hexadecimal. 3cf3c q8 Convert the hexadecimal number 4F6A to binary. Q9 Convert the binary number 0.1001001 to Decimal. Each place right to the radix is 1/2 the weight of its left hand neighbour. This binary number has a decimal value of 1/2+1/16+1/128= (64+8+1)/128= 73/128= 0.5703125 Q10 Convert the binary number 1110010.11 to Decimal. Each place right to the radix is 1/2 the weight of its left hand neighbour. Likewise, each place left of the radix is twice the weight of its right hand neighbour. This binary number has a decimal value of 26+25+24+21+1/2+1/4= 114.75. Q11 Add the following binary numbers.110111111+110111111 This question pertains to binary addition. Below is an image that explains binary addition. 110111111 110111111 1101111110 q 14 œThis is EASY! q 15 q 16 As outlined by our text, 1 Gegabyte can hold 20000 pages of pure 16-bit Unicode text. We know that 1 GB= 1024 MB. Therefore 1024/20000=650/x. By solving for x we find that a 650 MB CD-ROM can hold 12695.3125 pages.